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exterior covariant derivative : ウィキペディア英語版
exterior covariant derivative

In mathematics, the exterior covariant derivative is an analog of an exterior derivative that takes into account the presence of a connection.
==Definition==
Let ''G'' be a Lie group and ''P'' → ''M'' be a principal ''G''-bundle on a smooth manifold ''M''. Suppose there is a connection on ''P'' so that it gives a natural direct sum decomposition of each tangent space T_u P = H_u \oplus V_u into the horizontal and vertical subspaces. Let h: T_u P \to H_u be the projection.
If ϕ is a ''k''-form on ''P'' with values in a vector space ''V'', then its exterior covariant derivative ''D''ϕ is a form defined by
:D\phi(v_0, v_1,\dots, v_k)= d \phi(h v_0 ,h v_1,\dots, h v_k)
where ''v''''i'' are tangent vectors to ''P'' at ''u''.
Suppose ''V'' is a representation of ''G''; i.e., there is a Lie group homomorphism ρ: ''G'' →''GL''(''V''). If ''φ'' is equivariant in the sense:
:R_g^
* \phi = \rho(g)^\phi
where R_g(u) = ug, then ''D''ϕ is a tensorial (''k'' + 1)-form on ''P'' of the type ρ: it is equivariant and horizontal (a form ψ is horizontal if ψ(''v''0, …, ''v''k) = ψ(''hv''0, …, ''hv''''k'').)
*Example: if ω is the connection form on ''P'', then Ω = ''D''ω is called the curvature form of ω. Bianchi's second identity says the exterior covariant derivative of Ω is zero; i.e., ''D''Ω = 0.
We also denote the differential of ρ at the identity element by ρ:
:\rho: \mathfrak \to \mathfrak(V).
If φ is a tensorial ''k''-form of type ρ, then
:D \phi = d \phi + \rho(\omega) \cdot \phi,〔If ''k'' = 0, then, writing X^ for the fundamental vector field (i.e., vertical vector field) generated by ''X'' in \mathfrak on ''P'', we have:
:d \phi(X^_u) = |_0 \phi(u \operatorname(tX)) = -\rho(X)\phi(u) = -\rho(\omega(X^_u))\phi(u),
since φ(''gu'') = ρ(''g''−1)φ(''u''). On the other hand, ''D''φ(''X''#) = 0. If ''X'' is a horizontal vector field, then D \phi(X) = d\phi(X) and \omega(X) = 0. In general, by the invariant formula for exterior derivative, we have: for any vector fields ''X''''i'''s, since φ takes the same values at ''hX''''i'''s and ''X''''i'''s,
:\begin
&D \phi(X_0, \dots, X_k) - d \phi(X_0, \dots, X_k) = \sum_0^k (-1)^i \rho(\omega(X_i)) \phi(X_0, \dots, \widehat, \dots, X_k) \\
&= \sum_0^k (-1)^i \rho(\omega(X_i)) \sum_} \operatorname(\sigma) \phi(X_, \dots, \widehat)
\end

where the hat means the term is omitted. This equals (\rho(\omega) \cdot \phi)(X_0, \cdots, X_k).〕
where \rho(\omega) is a \mathfrak(V)-valued form, and
:(\rho(\omega) \cdot \phi)(v_1, \dots, v_) = 1/! \sum_ \operatorname(\sigma)\rho(\omega(v_)) \phi(v_, \dots, v_).
*Example: Bianchi's second identity (''D''Ω = 0) can be stated as: d\Omega + \operatorname(\omega) \cdot \Omega = 0.
Unlike the usual exterior derivative, which squares to 0 (that is d2 = 0), we have:
:D^2\phi=F \cdot \phi,〔Proof: We have:
:D^2 \phi = \rho(d \omega) \cdot \phi + \rho(\omega) \cdot (\rho(\omega) \cdot \phi) = \rho(d \omega) \cdot \phi + \rho((\wedge \omega )) \cdot \phi,
(cf. the example at Lie algebra-valued differential form#Operations), which is \rho(\Omega) \cdot \phi by E. Cartan's structure equation.〕
where ''F'' = ρ(Ω). In particular ''D''2 vanishes for a flat connection (i.e., Ω = 0).
If ρ: ''G'' →''GL''(''R''n), then one can write
:\rho(\Omega) = F = \sum _j _i
where _j is the matrix with 1 at the (''i'', ''j'')-th entry and zero on the other entries. The matrix _j whose entries are 2-forms on ''P'' is called the curvature matrix.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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